298. Binary Tree Longest Consecutive Sequence

Given a binary tree, find the length of the longest consecutive sequence path.

The path refers to any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The longest consecutive path need to be from parent to child (cannot be the reverse).

Example 1:

Input:

1
\
3
/ \
2 4
\
5

Output: 3

Explanation: Longest consecutive sequence path is 3-4-5, so return 3.
Example 2:

Input:

2
\
3
/
2

/
1

Output: 2

Explanation: Longest consecutive sequence path is 2-3, not 3-2-1, so return 2.

Solution

先序遍历,记录parent,因为要求child - parent == 1
注意:parent to children, 正序

Complexity

O(N) O(1)

Code

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
class Solution {
    private int res = 0;
    public int longestConsecutive(TreeNode root) {
        helper(root, null, 1);
        return res;
    }
    
    public void helper(TreeNode root, TreeNode parent, int length){
        if(root == null)
            return;
        if(parent != null){
            length = root.val - parent.val == 1 ? length + 1 : 1;
        }
        
        res = Math.max(res, length);
        
        helper(root.left, root, length);
        helper(root.right, root, length);
    }
}